Line voltage = √3 × phase voltage: proof
Three Phase Systems · Lesson 7 · Intermediate
Purpose
Derive the √3 magnitude and 30-degree angular relationship between balanced star line and phase voltages.
Learning objectives
- Form a line voltage
- Derive √3 geometrically
- State the 30° displacement
- Apply nominal-voltage caveats
A line-to-line voltage is the phasor difference between two line-to-neutral voltages. Because those phase phasors are 120 degrees apart, subtraction produces a magnitude √3 times one phase voltage.
Core theory
For positive sequence with Va as reference, Vab = Va − Vb. Subtraction means adding the opposite of Vb, not adding scalar rms values.
The resulting balanced magnitude is VL = √3 Vph, and the line voltage is displaced 30 degrees relative to the corresponding phase voltage under the stated labelling convention.
Thus an ideal 230 V phase-to-neutral system has about 398 V line-to-line, commonly described by a nominal 230/400 V system. Actual measured voltage and permitted tolerances require current supply data.
| Term | Meaning | Symbol | Unit |
|---|---|---|---|
| Line voltage | Voltage measured between two line conductors | VL | V |
| Phase voltage | Voltage from line to star point/neutral | Vph | V |
| Phasor subtraction | Vector difference defining voltage between two nodes | Not applicable | Not applicable |
VL = √3 × VphFor a balanced star system, line voltage magnitude is root-three times phase voltage.
VAssumptions: Balanced sinusoidal star set.
- Formula: VL = √3 Vph.
- Substitute: VL = 1.732 × 230 V.
- Calculate: VL ≈ 398 V, conventionally associated with a nominal 400 V system.
The ideal calculated line voltage is approximately 398 V.
Reasonableness check: It must be greater than 230 V but less than the scalar sum 460 V.
- Adding 230 + 230
- Using √3 for an unbalanced set without analysis
- Ignoring the 30° phase relation
Where this appears in practice
The relationship underpins equipment voltage selection, measurements, transformer connections, and power calculations.
Knowledge check
Why is line voltage not twice phase voltage?
The phase voltages are phasors 120° apart, not in-phase scalars. Their vector difference has magnitude √3 times one phase value.
Answer: The phase voltages are phasors 120° apart, not in-phase scalars. Their vector difference has magnitude √3 times one phase value.
Practical exercise
Derive Vab from rectangular Va and Vb components and identify its magnitude and angle.
Summary
- Line voltage is a phasor difference
- Balanced magnitude ratio is √3
- A 30° displacement accompanies the ratio
Sources and review
- IEC 60038: IEC standard voltages: IEC; 2009+A1:2021; International
- Broken PEN: IET Wiring Matters; Issue 84, 2021; United Kingdom
- Minimizing unnecessary live testing for initial verification: IET Wiring Matters; Issue 105, 2025; United Kingdom
Editorial review date: 2026-08-22. Professional electrical review is pending.