Line current = √3 × phase current: proof
Three Phase Systems · Lesson 11 · Intermediate
Purpose
Derive the √3 magnitude and 30-degree angular relationship between balanced delta line and phase currents.
Learning objectives
- Form a line-current equation
- Derive the magnitude ratio
- State angular displacement
- Apply the relation only to balanced sets
At a delta terminal, line current is the vector difference between the two branch currents meeting there. Equal branch currents separated by 120 degrees produce a resultant √3 times one branch current.
Core theory
With declared current directions, a representative relation is IA = IAB − ICA. The exact signs and 30-degree lead/lag statement depend on the adopted sequence and reference convention.
For a balanced positive-sequence delta, |IL| = √3|Iph|. The line current is displaced by 30 degrees from its associated phase current under the chosen convention.
The shortcut does not directly solve unbalanced impedances, missing branches, harmonic components, or distorted currents; those require complex branch analysis and KCL.
| Term | Meaning | Symbol | Unit |
|---|---|---|---|
| Line current | Current delivered through one line terminal | IL | A |
| Branch current | Current within one delta side | Iph | A |
| Current displacement | Angular difference between associated line and branch current | Not applicable | Not applicable |
|IL| = √3 × |Iph|Balanced delta line-current magnitude is root-three times phase-current magnitude.
AAssumptions: Balanced sinusoidal currents.
- Formula: IL = √3 Iph.
- Substitute: IL = 1.732 × 12 A.
- Calculate: IL ≈ 20.8 A.
Line-current magnitude is approximately 20.8 A.
Reasonableness check: The vector result is greater than 12 A but less than the scalar sum 24 A.
- Multiplying voltage by √3 in delta
- Omitting the 30° relationship
- Using the balanced formula after a branch opens
Where this appears in practice
The relationship supports delta load, winding, protective-device, and conductor calculations.
Knowledge check
Why is delta line current not twice branch current?
The two branch currents combine as phasors, not in-phase scalars. Their vector difference produces the √3 ratio.
Answer: The two branch currents combine as phasors, not in-phase scalars. Their vector difference produces the √3 ratio.
Practical exercise
Resolve two 12 A branch-current phasors into rectangular components and reproduce 20.8 A.
Summary
- Line current is a phasor difference
- Balanced magnitude ratio is √3
- Unbalance needs full analysis
Sources and review
- IEC 60038: IEC standard voltages: IEC; 2009+A1:2021; International
- IEC 61921: Low-voltage power-factor-correction banks: IEC; 2017; International
- Harmonics and Power Quality Analysis webinar Q&A: IET; Current online guidance; United Kingdom
Editorial review date: 2026-08-22. Professional electrical review is pending.