Ohm's Law: derivation and examples
Electrical Fundamentals · Lesson 9 · Beginner
Purpose
Apply Ohm's law with units, substitution, checks, and awareness of its limits.
Learning objectives
- Use all three Ohm's-law forms
- Show substitutions with units
- Check answers by inverse calculation
- Identify non-ohmic behavior
Ohm's law connects voltage, current, and resistance for a component when its physical conditions are sufficiently constant.
Core theory
For an ohmic component at constant temperature, current is proportional to voltage and the ratio V/I is constant.
The three useful forms are V = IR, I = V/R, and R = V/I. Choose the form that leaves the required quantity alone.
Lamps, diodes, thermistors, motors, and many electronic loads are not described by one constant resistance across all operating points.
| Term | Meaning | Symbol | Unit |
|---|---|---|---|
| Ohmic | Having an approximately constant V/I ratio under stated conditions | Not applicable | Not applicable |
| Operating point | The specific voltage and current at which a device is working | Not applicable | Not applicable |
| I–V characteristic | Graph showing current response to applied voltage | Not applicable | Not applicable |
V = I × R | I = V ÷ R | R = V ÷ IUse volts, amperes, and ohms together; convert prefixes first.
V = A·Ω; A = V/Ω; Ω = V/AAssumptions: The coil is represented as 120 Ω at this operating condition; Supply and conductor drop are neglected.
- Current formula: I = V/R.
- Current substitution: I = 24 V ÷ 120 Ω = 0.200 A.
- Power check: P = VI = 24 V × 0.200 A = 4.8 W.
- Inverse check: IR = 0.200 A × 120 Ω = 24 V.
Current is 0.200 A (200 mA); power is 4.8 W.
Reasonableness check: A resistance five times the voltage number gives one-fifth of an ampere; the inverse check returns the supply voltage.
- Entering milliamperes as amperes
- Multiplying when the required form needs division
- Applying a cold resistance to a hot filament or energized coil without qualification
Where this appears in practice
Ohm's law supports sensor-loop checks, coil-current estimates, resistor selection, and first-pass fault diagnosis.
Knowledge check
A 48 V circuit carries 0.40 A. What resistance does it present?
120 Ω. R = V/I = 48 V ÷ 0.40 A = 120 Ω.
Answer: 120 Ω. R = V/I = 48 V ÷ 0.40 A = 120 Ω.
Practical exercise
Choose a safe low-voltage resistor example, calculate expected current and power, then compare with a simulator or supervised bench measurement.
Summary
- Choose the rearranged form for the unknown
- Carry units through every step
- Check with an inverse calculation
- State when resistance may change
Sources and review
- The Feynman Lectures on Physics, Volume II: Caltech; Online edition; Physics reference
- International Electrotechnical Vocabulary: Electromagnetism: IEC; Current edition must be confirmed; International
Editorial review date: 2026-08-14. Professional electrical review is pending.