Voltage dividers and current dividers
Electrical Fundamentals · Lesson 14 · Beginner
Purpose
Use unloaded voltage dividers and two-branch current dividers while recognising loading limits.
Learning objectives
- Calculate divider output voltage
- Calculate two-branch current division
- Explain loading error
- Check limiting cases
Divider rules are shortcuts derived from series and parallel laws; they are valid only when their assumptions match the circuit.
Core theory
For two series resistors, the unloaded output across R₂ is Vin R₂/(R₁+R₂). A connected load sits in parallel with R₂ and changes the ratio.
For two parallel resistors, current through R₁ equals total current times R₂/(R₁+R₂); current favours the lower resistance.
Divider networks dissipate power continuously and often need buffering when driving a load.
| Term | Meaning | Symbol | Unit |
|---|---|---|---|
| Voltage divider | Series network producing a fraction of input voltage | Not applicable | Not applicable |
| Current divider | Parallel network splitting total current | Not applicable | Not applicable |
| Loading | Output change caused by a connected load | Not applicable | Not applicable |
Vout = Vin·R₂/(R₁+R₂); I₁ = It·R₂/(R₁+R₂)The current-divider numerator uses the other branch resistance.
V and AAssumptions: Output load impedance is effectively infinite.
- Ratio: R₂/(R₁+R₂) = 5/(10+5) = 1/3.
- Output: Vout = 15 × 1/3 = 5 V.
- Check: Series current is 1 mA; drops are 10 V and 5 V.
The unloaded output is 5 V.
Reasonableness check: The lower resistor is one-third of total resistance, so it receives one-third of the voltage.
- Ignoring load resistance
- Using the wrong resistor in the numerator
- Applying current division to series components
Where this appears in practice
Dividers scale sensor signals, establish reference levels, and estimate branch currents, but precision designs account for tolerance and loading.
Knowledge check
What happens when a finite load is added across the lower divider resistor?
Its effective resistance falls and the output voltage usually falls. The load is parallel with the lower resistor.
Answer: Its effective resistance falls and the output voltage usually falls. The load is parallel with the lower resistor.
Practical exercise
Calculate a 9 V divider using 2 kΩ and 1 kΩ, then repeat with a 1 kΩ load across the lower resistor.
Summary
- Divider rules come from network laws
- Loading changes voltage division
- A divider does not provide isolation
Sources and review
- The International System of Units (SI Brochure): BIPM; 9th edition, updated 2026; International
- SI Units: Electric Current: NIST; Current web edition; United States / SI reference
- University Physics Volume 2: OpenStax; Current web edition; Physics reference
Editorial review date: 2026-08-21. Professional electrical review is pending.