Potential difference: the driving force
Electrical Fundamentals · Lesson 6 · Beginner
Purpose
Distinguish voltage from current and use potential difference correctly when describing a circuit.
Learning objectives
- Define potential difference
- Relate one volt to one joule per coulomb
- Measure voltage in parallel
- Explain source voltage and component voltage drop
Voltage describes an energy difference between two points. It is not a substance flowing through a wire: it tells us how much energy each coulomb could transfer moving between those points.
Core theory
A source separates charge and establishes an electric potential difference. A load converts electrical energy into heat, light, motion, or another form.
Potential is defined at a point relative to a reference; voltage is the difference between two potentials. That is why a voltmeter always uses two probes.
Across a closed-loop circuit, voltage rises supplied by sources balance voltage drops across loads when stored energy is not changing.
| Term | Meaning | Symbol | Unit |
|---|---|---|---|
| Potential difference | Energy transferred per unit charge between two points | V | volt (V) |
| Charge | Quantity of electricity | Q | coulomb (C) |
| Energy | Capacity to do work | E | joule (J) |
V = E ÷ QPotential difference equals energy transferred divided by charge moved.
1 V = 1 J/CAssumptions: The stated energy is electrical energy transferred by the lamp; Values refer to the same interval.
- Identify: E = 24 J and Q = 2 C.
- Substitute: V = E ÷ Q = 24 J ÷ 2 C.
- Calculate: V = 12 J/C = 12 V.
The potential difference across the lamp is 12 V.
Reasonableness check: Each coulomb transfers 12 joules, so two coulombs transfer 24 joules.
- Calling voltage a flow
- Quoting a voltage without identifying the two points
- Connecting a voltmeter in series
Where this appears in practice
Technicians compare measured voltage at the supply and load to locate excessive drop in cables or connections.
Knowledge check
A device transfers 60 J for 5 C. What voltage is across it?
12 V. Use V = E/Q: 60 J ÷ 5 C = 12 J/C.
Answer: 12 V. Use V = E/Q: 60 J ÷ 5 C = 12 J/C.
Practical exercise
On a de-energised battery circuit or simulator, label the two points for each voltage reading before calculating or measuring it.
Summary
- Voltage is an energy difference, not a flow
- It is measured between two points
- One volt equals one joule per coulomb
Sources and review
- The Feynman Lectures on Physics, Volume II: Caltech; Online edition; Physics reference
- International Electrotechnical Vocabulary: Electromagnetism: IEC; Current edition must be confirmed; International
Editorial review date: 2026-08-14. Professional electrical review is pending.